Calculus is how different things vary with respect to one another. There are two main components, differentiation and integration. We will do an integration problem here.
Integration by substitution is highly unlikely to be effective in this case. Hence, let’s try integration by parts, setting f(x)=Ln (x)^2 and g(x)=1
Then, the integral becomes xLn (x)^2 minus the integral of x times 1/x times 2Lnx dx. Then we do integration by parts once again, with f(x)=lnx and g(x)=1 and the ultimate answer is xLn (x)^2-2xLn (x)+2x+C, where C is an arbitrary constant.
About The Author
|I am currently an undergraduate student at UC Berkeley who is pre-med and a prospective Molecular and Cell Biology student. While math is not my sole focus, I love helping students understand math concepts better and perform better on their tests. My friends always say that I explain concepts very c...|