## Calculus Tutorial

*chain rule*

#### Intro

The chain rule tells us how to take the derivative of their composition

d/dx(f(g(x)))=f'(g(x)).g'(x)

#### Sample Problem

y=cos(e(x3+x))

find dy/dx

#### Solution

y=cos(e(x3+x))

u(x)=e(x3+x) difine u(x)

y=cos(u) express y in term of u

dy/dx=dy/du.du/dx chain rule

dy/dx=d/du(cos(u)).d/dx(e(x3+x)) substitute y(u) and u(x)

dy/dx=-sin(u).e(x3+x).(3×2+1) evaluate derivative

dy/dx=-sin(e(x3+x)).e(x3+x).(3×2+1) substite u in term of x

# About The Author

Mathematics Teacher |

I was a teacher in Srilanka from 1992 to 2006. I took tuition from 1990 to 1991 in India. I do general work in Canada but I help to do homework to my daughters. I finished my teacher\'s training college diploma in Srilanka. I completed my B.Sc degree course at Bharayiar university in India. |