## Calculus Tutorial

*Derivatives of inverse trigonometric function*

#### Sample Problem

#### Solution

y=arctan(x/3)

dy/dx=d/dx(arctan(x/3) — differentiate

=1/(1+(x/3)2).1/3 — chain rule

=9/(9+x2).1/3 — simlify

=3/(9+x2)

=3/(9+1) — substitute x=1

=3/10

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I was a teacher in Srilanka from 1992 to 2006. I took tuition from 1990 to 1991 in India. I do general work in Canada but I help to do homework to my daughters. I finished my teacher\'s training college diploma in Srilanka. I completed my B.Sc degree course at Bharayiar university in India. |

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