Differentiating trigonometric function

Calculus Tutorial

Differentiating trigonometric function

Intro

d/dx(sinx)=cosx
d/dx(cosx)=-sinx
d/dx(tanx)=(secx)2

Sample Problem

Let y=sin(4x-π/3)
What is the value of dy/dx at x=π/6

Solution

Let y=sin(4x-π/3)
dy/dx=cos(4x-π/3).4 differentiate
dy/dx at (x=π/6) =cos(4.π/6-π/3).4 substituting
=4.cos(2π/3-π/3) simplify
=4.cos(π/3)
=4.1/2
=2



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I was a teacher in Srilanka from 1992 to 2006. I took tuition from 1990 to 1991 in India. I do general work in Canada but I help to do homework to my daughters. I finished my teacher\'s training college diploma in Srilanka. I completed my B.Sc degree course at Bharayiar university in India.
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