Calculus Tutorial
Differentiating using multiple rules
Sample Problem
Solution
Y=2×3√(3×2+1)
dy/dx=d/dx(2×3√(3×2+1)) — differentiate
=d/dx(2×3). √(3×2+1)+d/dx√(3×2+1).2×3 — product rule
=6×2. √(3×2+1)+1/2.(1/√(3×2+1)).6x.2×3 — chain rule and power rule
=6×2. √(3×2+1)+12×4/(2√(3×2+1)) — simplify
=(12×2(3×2+1)+12×4)/( 2√(3×2+1))
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