exponential function

Calculus Tutorial

exponential function

Intro

y=v(u(x)) — dy/dx=v'(u(x)).u'(x)
(1) d/dx(sinx)=cosx
(2) d/dx(cosx)=-sinx
(3) d/dx(tanx)=(secx)2

Sample Problem

y=e(tanx).sin(e)(x2+2x+1)
find dy/dx

Solution

y=e(tanx).sin((e)(x2+2x+1))
dy/dx=d/dx(e(tanx).sin(e)(x2+2x+1))
dy/dx=e(tanx).d/dx(sin(e)(x2+2x+1))+sin(e)(x2+2x+1).d/dx(e(tanx)) — product rule
d/dx(sin(e)(x2+2x+1)=cos(e)(x2+2x+1).e(x2+2x+1).(2x+2) — chain rule
d/dx((e)tanx)=e(tanx).(secx)2 — chain rule
dy/dx=e(tanx).cos(e)(x2+2x+1).e(x2+2x+1).(2x+2)+sin(e)(x2+2x+1).e(tanx).(secx)2 — substitute



About The Author

Mathematics Teacher
I was a teacher in Srilanka from 1992 to 2006. I took tuition from 1990 to 1991 in India. I do general work in Canada but I help to do homework to my daughters. I finished my teacher\'s training college diploma in Srilanka. I completed my B.Sc degree course at Bharayiar university in India.
13 Subjects
KnowRo Tutor
28 Tutorials
Montréal, QC
Get Tutoring Info

Suggested Tutors for Calculus Help

Abdul B

Arlington, VA

Math And Science Expert

Siddarth C

Vienna, VA

All Subjects

Emily V

Alexandria, VA

Versatile And Flexible Tutor

Maxine J

Bethesda, MD

Any Topic, Any Language

^