applying both the product rule and chain rule.
dy/dx=e(sinx).d/dx(sin(ex))+sin(ex).d/dx(e(sinx)) product rule
d/dx(sin(ex))=cos(ex).ex chain rule
d/dx(e(sinx))=e(sinx).cosx chain rule
dy/dx=e(sinx).cos(ex).ex + sin(ex).e(sinx).cosx
About The Author
|I was a teacher in Srilanka from 1992 to 2006.I took tuition from 1990 to 1991 in India.I do general work in Canada but I help to do homework to my daughters.I finished my teachers training college diploma in Srilanka.|