## Calculus Tutorial

*Implicit differentiation*

#### Intro

power rule d/dx(xn)=nx(n-1)

chain rule (f(g(x))’=f'(g(x)).g(x)

#### Sample Problem

√x.y=3

Find dy/dx

#### Solution

√x.y=3

d/dx(√x.y)=d/dx(3) — defferentiate

d/dx(√x).y+√x.d/dx(y)=0

1/2.(1/√(x)).y+√x.1.dy/dx=0 — power rule and chain rule

y/2√x+√x.dy/dx=0 — simplify

√x.dy/dx=-y/2√x

dx/dy=-y/2. (√x. √x)

dy/dx=- y/2x

# About The Author

Mathematics Teacher |

I was a teacher in Srilanka from 1992 to 2006. I took tuition from 1990 to 1991 in India. I do general work in Canada but I help to do homework to my daughters. I finished my teacher\'s training college diploma in Srilanka. I completed my B.Sc degree course at Bharayiar university in India. |

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