Implicit differentiation

Calculus Tutorial

Implicit differentiation


power rule d/dx(xn)=nx(n-1)
chain rule (f(g(x))’=f'(g(x)).g(x)

Sample Problem

Find dy/dx


d/dx(√x.y)=d/dx(3) — defferentiate
1/2.(1/√(x)).y+√x.1.dy/dx=0 — power rule and chain rule
y/2√x+√x.dy/dx=0 — simplify
dx/dy=-y/2. (√x. √x)
dy/dx=- y/2x

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