Implicit differentiation

Calculus Tutorial

Implicit differentiation

Intro

power rule d/dx(xn)=nx(n-1)
chain rule (f(g(x))’=f'(g(x)).g(x)

Sample Problem

√x.y=3
Find dy/dx

Solution

√x.y=3
d/dx(√x.y)=d/dx(3) — defferentiate
d/dx(√x).y+√x.d/dx(y)=0
1/2.(1/√(x)).y+√x.1.dy/dx=0 — power rule and chain rule
y/2√x+√x.dy/dx=0 — simplify
√x.dy/dx=-y/2√x
dx/dy=-y/2. (√x. √x)
dy/dx=- y/2x



About The Author

Mathematics Teacher
I was a teacher in Srilanka from 1992 to 2006. I took tuition from 1990 to 1991 in India. I do general work in Canada but I help to do homework to my daughters. I finished my teacher\'s training college diploma in Srilanka. I completed my B.Sc degree course at Bharayiar university in India.
13 Subjects
KnowRo Tutor
28 Tutorials
Montréal, QC
Get Tutoring Info

Suggested Tutors for Calculus Help

Krista L

Salem, NH

Math Expert

Paul P

Dover, NH

Math Subject Matter Expert And SAT Instructor

Salme C

Dover, NH

Engineer With Teaching/Tutoring Experience

Brent A

Seabrook, NH

Chemistry And Physics

^