## Calculus Tutorial

*Implicit differentiation(advanced)*

#### Intro

d/dx(sinx)=cosx

d/dx(y)=1.dy/dx

#### Sample Problem

y=sin(3x+2y)

find dy/dx

#### Solution

y=sin(3x+2y)

d/dx(y)=d/dx.sin(3x+2y) — differentiate

1.dy/dx=cos(3x+2y).(3+2.dy/dx) — chain rule

dy/dx=3.cos(3x+2y)+2dy/dx.cos(3x+2y) — simplify

(1-2cos(3x+2y))dy/dx=3cos(3x+2y)

dy/dx=3cos(3x+2y)/(1-2cos(3x+2y)

# About The Author

Mathematics Teacher |

I was a teacher in Srilanka from 1992 to 2006. I took tuition from 1990 to 1991 in India. I do general work in Canada but I help to do homework to my daughters. I finished my teacher\'s training college diploma in Srilanka. I completed my B.Sc degree course at Bharayiar university in India. |

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