Using the Ideal Gas Law to determine the molecular weight of an unknown compound

Chemistry Tutorial

Using the Ideal Gas Law to determine the molecular weight of an unknown compound

Intro

Suppose you have a gas that you can reliably assume is an ideal gas, and that there is only one species present. You know the mass of the sample, and you have it confined at a known pressure, volume, and temperature. What is the molecular weight of the unknown gas?

Sample Problem

An ideal gas kept at 1.000 atm, 24.85 Celsius, and 4.000 Liters weighs 4.5824 grams. What is the molar mass of the gas?

Solution

Since we are given the information that the gas is ideal, we can use the ideal gas law (PV = nRT). We are given P, V, and T, but T is in celsius. We need to convert this to kelvin: 24.85 + 273.15 = 298.00K.

We can now rearrange to solve for n, the number of moles:
n = PV/RT = (1 atm)*(4L)/((0.08206 L*atm/mol*k)*(298.00K)) = about 0.1636 moles.

So we now have the mass, and the number of moles of gas. Molar mass is moles/mass, so the molecular weight of the gas is 4.5824 grams / 0.1636 moles, or 28.01 grams/mole.



About The Author

Chemistry Tutor With Some Math Knowledge
I am a recent graduate from Tennessee Technological University with a bachelors in chemical engineering. During my time there I was employed as a general chemistry tutor during my junior and senior semesters. I have completed two semesters in General Chemistry, Organic Chemistry, and Physical Chemis...
Send Email
8 Subjects
KnowRo Tutor
2 Tutorials
$20
Soddy-Daisy, TN
Learn

Suggested Tutors for Chemistry Help

Ad

Varsity Tutors

(855) 475-5132 - Award-Winning Academic & Test Prep Tutors

Ad

Air Tutors

One-on-One Ivy Tutoring Partners 24/7

Ad

Link Educational Institute

Link Educational Institute

Siddarth C

Vienna, VA

All Subjects

Leave a Comment

Your email address will not be published. Required fields are marked *

^