### Mathematics Teacher ## Profile

I was a teacher in Srilanka from 1992 to 2006. I took tuition from 1990 to 1991 in India. I do general work in Canada but I help to do homework to my daughters. I finished my teacher's training college diploma in Srilanka. I completed my B.Sc degree course at Bharayiar university in India.

#### Education

Bsc Mathematics India

## Subjects of Expertise

SAT Math, ACT Math, GRE Math, GMAT Math, Pre-Algebra, Algebra 1, Algebra 2, Geometry, Trigonometry, Calculus, Statistics, Pre-Calculus, Elementary Math (K-6th)

## Contact Rahulakumar S

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# 28 Tutorials by Rahulakumar S

## exponential function Posted by: Rahulakumar S on Apr 11, 2018

y=v(u(x)) — dy/dx=v'(u(x)).u'(x) (1) d/dx(sinx)=cosx (2) d/dx(cosx)=-sinx (3) d/dx(tanx)=(secx)2

## Differentiating related function Posted by: Rahulakumar S on Apr 10, 2018

d/dt(sinx(t))=d/dx(sinx).dx/dt d/dt(cosy(t))=d/dy(cosy).dy/dt

## Differentiating using multiple rules Posted by: Rahulakumar S on Apr 09, 2018

We will need to use the product rule and chain rule

## Differentiating using multiple rule Posted by: Rahulakumar S on Apr 09, 2018

using the chain rule and product rule

## Parametric functions differentiation Posted by: Rahulakumar S on Apr 09, 2018

In general, to find the derivative of a function defined parametrically by the equations x=u(t), y=v(t), we use the following rule dy/dx=(dy/dt).(dt/dx)=v(t)/u(t)

## Second Derivative parametric function Posted by: Rahulakumar S on Apr 09, 2018

x=u(t) dx/dt=U'(t) y=v(t) dy/dt=v'(t) dy/dx=dy/dt.dt/dx d2y/dx2=d/dt(dy/dx).dt/dx

## Negative power differentiation Posted by: Rahulakumar S on Apr 09, 2018

We can rewrite each rational term in the expression as a negative power of x

## Derivatives of inverse trigonometric function Posted by: Rahulakumar S on Apr 04, 2018

the formula for the derivative of arctan(x)=1/(1+x2).

## Implicit differentiation Posted by: Rahulakumar S on Apr 04, 2018

In implicit differentiation, we differentiate both sides of the equation according to x and treat y as an implicit function of x

## Implicit differentiation(advanced) Posted by: Rahulakumar S on Apr 04, 2018

d/dx(sinx)=cosx d/dx(y)=1.dy/dx

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