Rahulakumar S

Montréal, QC, Canada

Mathematics Teacher

$25/hr

Profile

I was a teacher in Srilanka from 1992 to 2006. I took tuition from 1990 to 1991 in India. I do general work in Canada but I help to do homework to my daughters. I finished my teacher's training college diploma in Srilanka. I completed my B.Sc degree course at Bharayiar university in India.

Education

Bsc Mathematics India

Subjects of Expertise

SAT Math, ACT Math, GRE Math, GMAT Math, Pre-Algebra, Algebra 1, Algebra 2, Geometry, Trigonometry, Calculus, Statistics, Pre-Calculus, Elementary Math (K-6th)

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28 Tutorials by Rahulakumar S

exponential function

y=v(u(x)) — dy/dx=v'(u(x)).u'(x) (1) d/dx(sinx)=cosx (2) d/dx(cosx)=-sinx (3) d/dx(tanx)=(secx)2

Differentiating related function

d/dt(sinx(t))=d/dx(sinx).dx/dt d/dt(cosy(t))=d/dy(cosy).dy/dt

Differentiating using multiple rules

We will need to use the product rule and chain rule

Differentiating using multiple rule

using the chain rule and product rule

Parametric functions differentiation

In general, to find the derivative of a function defined parametrically by the equations x=u(t), y=v(t), we use the following rule dy/dx=(dy/dt).(dt/dx)=v(t)/u(t)

Second Derivative parametric function

x=u(t) dx/dt=U'(t) y=v(t) dy/dt=v'(t) dy/dx=dy/dt.dt/dx d2y/dx2=d/dt(dy/dx).dt/dx

Negative power differentiation

We can rewrite each rational term in the expression as a negative power of x

Derivatives of inverse trigonometric function

the formula for the derivative of arctan(x)=1/(1+x2).

Implicit differentiation

In implicit differentiation, we differentiate both sides of the equation according to x and treat y as an implicit function of x

Implicit differentiation(advanced)

d/dx(sinx)=cosx d/dx(y)=1.dy/dx

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